3t^2+2500t-2000000=0

Solution for 3t^2+2500t-2000000=0 equation:

3t^2+2500t-2000000=0

a = 3; b = 2500; c = -2000000;
Δ = b2-4ac
Δ = 25002-4·3·(-2000000)
Δ = 30250000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{30250000}=5500$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2500)-5500}{2*3}=\frac{-8000}{6}
=-1333+1/3
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2500)+5500}{2*3}=\frac{3000}{6}
=500
$